About us | Feedback

pH calculation - questions

pH questions

BATE pH calculator

operating systems:
XP, Vista, 7, 8, 10

single user license price:
€24.95 - approximately $33

Buy Now!

download 30-day free trial!
30-day money back guarantee!

pH calculation questions » pH of strong acid and base mixtures

What is pH of mixture prepared by mixing 20 mL 0.07 M NaOH and 13 mL 0.09 M HCl?

Although you are asked about pH, this is a simple limiting reagent question.

When you mix strong acid and strong base they react till one of the reagents runs out. What is left is responsible for pH.

Reaction taking place in the solution is

NaOH + HCl -> NaCl + H2O

Initially there were 20×0.07=1.4 mmol of NaOH and 13×0.09=1.17 mmol of HCl. They react 1:1, so after reaction 1.4-1.17=0.23 mmol of NaOH is left. Final volume of the solution is 20+13=33 mL, thus final concentration of NaOH left is 0.23/33=0.0070 M. pOH=-log(0.0070)=2.15 and pH=14-2.15=11.85.

Note that if there is exactly the same amount of both reactants reaction proceeds to the end - and you are left with perfectly neutral solution of pH=7.00.

If you want to check your skill at solving similar questions, please visit www.chemistry-quizzes.info and select problems from the Acid/base equilibrium section. To check your answers you will need to register - for free.

Questions? Comments? Feel free to discuss this page content at the chemistry quizzes forum (requires free registration).


Chemical calculator software for pH calculation, concentration conversion solution preparation and chemical equation balancing chemical calculator